Question

If $|x+2|\le 9$ then

• A. $x\in (-7,11)$
• B. $x\in [-11,7]$
• C. $x\in (-\infty ,-7)\cup (11,\infty )$
• D. $x\in (-\infty ,-7)\cup [11,\infty )$

Answer 1

Answer: (B)

$-9\le x+2\le 9$
$-11\le x\le 7$
$\therefore x\in [11,7]$