Question

If $|x+2| \leq 9$ then

• A. $x \in(-7,11)$
• B. $x \in[-11,7]$
• C. $x \in(-\infty,-7) \cup(11, \infty)$
• D. $x \in(-\infty,-7) \cup[11, \infty)$

Answer 1

Answer: (B)

$-9 \leq x+2 \leq 9$
$-11 \leq x \leq 7$
$\therefore x \in[11,7]$