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Tardigrade
Question
Physics
If work is done on the system in an adiabatic process,
Q. If work is done on the system in an adiabatic process,
508
161
Thermodynamics
Report Error
A
T
f
<
T
i
0%
B
T
f
=
T
i
100%
C
T
f
>
T
i
0%
D
information is insufficient
0%
Solution:
In adiabatic process, heat remains constant.
So, from first law of thermodynamics
Δ
Q
=
Δ
U
+
Δ
W
⇒
Δ
U
+
Δ
W
=
0
When work is done on system,
Δ
W
=
−
v
e
⇒
Δ
U
=
−
Δ
W
=
+
v
e
As,
Δ
U
=
μ
C
V
Δ
T
=
+
v
e
⇒
Δ
T
=
+
v
e
⇒
T
increases or
T
f
>
T
i
.