1. Tardigrade
  2. Question
  3. Physics
  4. If work is done on the system in an adiabatic process,

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If work is done on the system in an adiabatic process,

Thermodynamics

Solution:

In adiabatic process, heat remains constant.
So, from first law of thermodynamics
$\Delta Q=\Delta U+\Delta W$
$\Rightarrow \Delta U+\Delta W=0$
When work is done on system, $ \Delta W=- ve$
$\Rightarrow \Delta U=-\Delta W=+ ve $
As, $ \Delta U=\mu C_{V} \Delta T=+ ve$
$ \Rightarrow \Delta T=+ ve $
$\Rightarrow T$ increases or $T_{f}>T_{i} .$