If volume of 2 moles of an ideal gas at 540 K is 44.8 litre, then its pressure will be

Question

If volume of 2 moles of an ideal gas at 540 K is 44.8 litre, then its pressure will be (A) 1 atm (B) 3 atm (C) 2 atm (D) 4 atm

Tardigrade Admin · Accepted Answer

Number of moles, n = 2 Temperature, T = 540 K Volume, V = 44.8 L P=? [R, gas constant = 0.0821 L atm K-1 mol-1] According to ideal gas equation PV = nRT P=(nRT/V)=(2×0.0821×540/44.8) =2 atm

Q. If volume of $2$ moles of an ideal gas at $540 K$ is $44.8$ litre, then its pressure will be

$1 a t m$

$3 a t m$

$2 a t m$

$4 a t m$

Number of moles, $n = 2$
Temperature, $T = 540 K$
Volume, $V = 44.8 L$
$P = ?$
[ $R$ , gas constant $= 0.0821 L a t m K^{- 1} m o l^{- 1}$ ]
According to ideal gas equation $P V = n RT$
$P = \frac{n RT}{V} = \frac{2 \times 0.0821 \times 540}{44.8}$
$= 2 a t m$

Q. If volume of 2 moles of an ideal gas at 540K is 44.8 litre, then its pressure will be

1atm

3atm

2atm

4atm