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Q. If volume of $2$ moles of an ideal gas at $540 \,K$ is $44.8$ litre, then its pressure will be

UP CPMTUP CPMT 2013States of Matter

Solution:

Number of moles, $n = 2$
Temperature, $T = 540\, K$
Volume, $V = 44.8\, L$
$P=?$
[$R$, gas constant $= 0.0821\, L \,atm \,K^{-1}\, mol^{-1}$]
According to ideal gas equation $PV = nRT$
$P=\frac{nRT}{V}=\frac{2\times0.0821\times540}{44.8}$
$=2\,atm$