Tardigrade
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Tardigrade
Question
Mathematics
If | veca|=2 and | vecb|=3 and the angle between veca and vecb is 120°, then the length of the vector |(1 /2) veca-(1/3) vecb| is
Q. If
∣
a
∣
=
2
and
∣
b
∣
=
3
and the angle between
a
and
b
is
12
0
∘
, then the length of the vector
∣
2
1
a
−
3
1
b
∣
is
981
129
KCET
KCET 2022
Vector Algebra
Report Error
A
2
B
6
1
C
3
D
1
Solution:
Correct answer is (c) 3