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Tardigrade
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Mathematics
If | veca|=2 and | vecb|=3 and the angle between veca and vecb is 120°, then the length of the vector |(1 /2) veca-(1/3) vecb| is
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Q. If $|\vec{a}|=2$ and $|\vec{b}|=3$ and the angle between $\vec{a}$ and $\vec{b}$ is $120^{\circ}$, then the length of the vector $|\frac{1} {2}^{\vec{a}}-\frac{1}{3}^{\vec{b}}|$ is
KCET
KCET 2022
Vector Algebra
A
2
B
$\frac{1}{6}$
C
3
D
1
Solution:
Correct answer is (c) 3