If unit of length and time is doubled, what will be the numerical value of g (acceleration due to gravity)?

Question

If unit of length and time is doubled, what will be the numerical value of g (acceleration due to gravity)? (A) Doubled (B) Halved (C) Four times (D) Same

Tardigrade Admin · Accepted Answer

If unit of length and time is double, then value of g will be halved. [g]=L1T- 2 = (L/T2) arrow (1/2/(1/2)2) arrow (1/2)

Q. If unit of length and time is doubled, what will be the numerical value of $g$ (acceleration due to gravity)?

Doubled

Halved

Four times

Same

If unit of length and time is double, then value of g will be halved.
$[g] = L^{1} T^{- 2}$ = $\frac{L}{T ^{2}} \to \frac{1/2}{( 1/2 ) ^{2}} \to \frac{1}{2}$

Q. If unit of length and time is doubled, what will be the numerical value of g (acceleration due to gravity)?

Doubled

Halved

Four times

Same

If unit of length and time is double, then value of g will be halved. [g]=L1T−2 = T2L​→(1/2)21/2​→21​

Q. If unit of length and time is doubled, what will be the numerical value of $g$ (acceleration due to gravity)?

If unit of length and time is double, then value of g will be halved.
$[g] = L^{1} T^{- 2}$ = $\frac{L}{T ^{2}} \to \frac{1/2}{( 1/2 ) ^{2}} \to \frac{1}{2}$