Q. If unit of length and time is doubled, what will be the numerical value of $g$ (acceleration due to gravity)?
NTA AbhyasNTA Abhyas 2022
Solution:
If unit of length and time is double, then value of g will be halved.
$\left[g\right]=L^{1}T^{- 2}$ = $\frac{L}{T^{2}} \rightarrow \frac{1/2}{\left(1/2\right)^{2}} \rightarrow \frac{1}{2}$
$\left[g\right]=L^{1}T^{- 2}$ = $\frac{L}{T^{2}} \rightarrow \frac{1/2}{\left(1/2\right)^{2}} \rightarrow \frac{1}{2}$