If two waves represented by y1=4 sin ω t and y2=3 sin (ω t+(π/3)) interfere at a point, the amplitude of the resulting wave will be about

Question

If two waves represented by y1=4 sin ω t and y2=3 sin (ω t+(π/3)) interfere at a point, the amplitude of the resulting wave will be about (A) 7 (B) 6 (C) 5 (D) 3.5

Tardigrade Admin · Accepted Answer

varphi=π / 3, a1=4, a2=3 So, A=√a12+a22+2 a1 ⋅ a2 cos varphi ⇒ A ≈ 6

Q. If two waves represented by $y_{1} = 4 sin ω t$ and $y_{2} = 3 sin (ω t + \frac{π}{3})$ interfere at a point, the amplitude of the resulting wave will be about

7

6

5

3.5

$φ = π /3, a_{1} = 4, a_{2} = 3$
So, $A = a_{1}^{2} + a_{2}^{2} + 2 a_{1} \cdot a_{2} cos φ$
$\Rightarrow A \approx 6$

Q. If two waves represented by y1​=4sinωt and y2​=3sin(ωt+3π​) interfere at a point, the amplitude of the resulting wave will be about

7

6

5

3.5

φ=π/3,a1​=4,a2​=3 So, A=a12​+a22​+2a1​⋅a2​cosφ​ ⇒A≈6

Q. If two waves represented by $y_{1} = 4 sin ω t$ and $y_{2} = 3 sin (ω t + \frac{π}{3})$ interfere at a point, the amplitude of the resulting wave will be about

$φ = π /3, a_{1} = 4, a_{2} = 3$
So, $A = a_{1}^{2} + a_{2}^{2} + 2 a_{1} \cdot a_{2} cos φ$
$\Rightarrow A \approx 6$