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Q. If two waves represented by $y_{1}=4 \sin \,\omega t$ and $y_{2}=3 \sin \left(\omega t+\frac{\pi}{3}\right)$ interfere at a point, the amplitude of the resulting wave will be about

Solution:

$\varphi=\pi / 3, a_{1}=4, a_{2}=3$
So, $A=\sqrt{a_{1}^{2}+a_{2}^{2}+2 a_{1} \cdot a_{2} \cos \varphi} $
$\Rightarrow A \approx 6$