Question

If two dice are thrown together. Probability that the sum of the numbers appearing on them is 7, is

• A. $\frac{5}{36}$
• B. $\frac{1}{6}$
• C. $\frac{7}{36}$
• D. $\frac{8}{36}$

Answer 1

Answer: (B)

The number of ways of getting the sum seven
$=\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}$
Total number of ways $=6\times 6=36$
$\therefore$ Required probability
$=\frac{6}{36}=\frac{1}{6}$