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Q.
If two dice are thrown together. Probability that the sum of the numbers appearing on them is 7, is
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Solution:
The number of ways of getting the sum seven
$ =\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\} $
Total number of ways $ =6\times 6=36 $
$ \therefore $ Required probability
$ =\frac{6}{36}=\frac{1}{6} $