If there are no heat losses, the heat released by the condensation of x gram of steam at 100° C into the water at 100° C can be used to convert y gram of ice at 0° C into the water at 100° C . Then the ratio of y:x is nearly

Question

If there are no heat losses, the heat released by the condensation of x gram of steam at 100° C into the water at 100° C can be used to convert y gram of ice at 0° C into the water at 100° C . Then the ratio of y:x is nearly (A) 1:1 (B) 2:1 (C) 3:1 (D) 4:1

Tardigrade Admin · Accepted Answer

(y × 80)+(y × 1 × 100)=(x × 540) ⇒ 180y=540x ⇒ (y/x)=3 ⇒ y:x=3:1

Q. If there are no heat losses, the heat released by the condensation of $x$ gram of steam at $10 0^{\circ} C$ into the water at $10 0^{\circ} C$ can be used to convert $y$ gram of ice at $0^{\circ} C$ into the water at $10 0^{\circ} C$ . Then the ratio of $y : x$ is nearly

$1 : 1$

$2 : 1$

$3 : 1$

$4 : 1$

$(y \times 80) + (y \times 1 \times 100) = (x \times 540)$
$\Rightarrow 180 y = 540 x$
$\Rightarrow \frac{y}{x} = 3$
$\Rightarrow y : x = 3 : 1$

Q. If there are no heat losses, the heat released by the condensation of x gram of steam at 100∘C into the water at 100∘C can be used to convert y gram of ice at 0∘C into the water at 100∘C . Then the ratio of y:x is nearly

1:1

2:1

3:1

4:1