Question

If the $Z{n}^{2+}/Zn$ electrode is diluted to 100 times then the change in emf :

• A. increase of 59 mV
• B. decrease of 59 mV
• C. increase of 29.5 mV
• D. decrease of 29.5 mV

Answer 1

Answer: (A)

We know; $E_{cell}=\frac{0.059}{2}\log \frac{1}{C}$ where C = 100 times $E_{cell}=-\frac{0.059}{2}\log \frac{1}{100}$ $=-\frac{0.059}{2}\times -2$ $0.059V=59mV$ Thus, if the $Z{n}^{2+}/Zn$ electrode is diluted to 100 times than the emf is increase of 59 mV.