Thank you for reporting, we will resolve it shortly
Q.
If the $ Z{{n}^{2+}}/Zn $ electrode is diluted to 100 times then the change in emf :
MGIMS WardhaMGIMS Wardha 2006
Solution:
We know; $ {{E}_{cell}}=\frac{0.059}{2}\log \frac{1}{C} $ where C = 100 times $ {{E}_{cell}}=-\frac{0.059}{2}\log \frac{1}{100} $ $ =-\frac{0.059}{2}\times -2 $ $ 0.059\text{ }V=59\text{ }mV $ Thus, if the $ Z{{n}^{2+}}/Zn $ electrode is diluted to 100 times than the emf is increase of 59 mV.