If the volume of closed vessel in which the following simple reaction is carried out is reduced to one-third of original volume, the rate of reaction becomes 2 NO ( g )+ O 2( g ) longrightarrow 2 NO 2( g )

Question

If the volume of closed vessel in which the following simple reaction is carried out is reduced to one-third of original volume, the rate of reaction becomes 2 NO ( g )+ O 2( g ) longrightarrow 2 NO 2( g ) (A) One-third (B) Three times (C) Nine times (D) Twenty seven times

Tardigrade Admin · Accepted Answer

V 2=( V 1/3) arrow C 2=3 C 1 (. conc. . propto (1/ text volume )) r 1= K [ NO ]2[ O 2] r 2 ⇒ K [3 NO ]2(3 O 2) ⇒ 27 K [ NO ]2[ O 2]=27 r 1

Q. If the volume of closed vessel in which the following simple reaction is carried out is reduced to one-third of original volume, the rate of reaction becomes
$2 NO (g) + O_{2} (g) ⟶ 2 N O_{2} (g)$

One-third

Three times

Nine times

Twenty seven times

$V_{2} = \frac{V _{1}}{3} \to C_{2} = 3 C_{1}$
$($ conc. $\propto \frac{1}{volume})$
$r_{1} = K [NO]^{2} [O_{2}]$
$r_{2} \Rightarrow K [3 NO]^{2} (3 O_{2})$
$\Rightarrow 27 K [NO]^{2} [O_{2}] = 27 r_{1}$

Q. If the volume of closed vessel in which the following simple reaction is carried out is reduced to one-third of original volume, the rate of reaction becomes 2NO(g)+O2​(g)⟶2NO2​(g)