Question

If the vertical component of earth's magnetic field at a place is $\sqrt{3}$ times the horizontal component, then the value of dip at that place is

• A. $60^{\circ }$
• B. $45^{\circ }$
• C. $30^{\circ }$
• D. $15^{\circ }$

Answer 1

Answer: (A)

Here, $B_V=\sqrt{3}{B}_H$
We know that, angle of dip, $\theta ={\tan }^{-1}\left(\frac{B_V}{B_H}\right)$
$\Rightarrow \theta ={\tan }^{-1}\left(\frac{\sqrt{3}{B}_H}{B_H}\right)={\tan }^{-1}(\sqrt{3})=60^{\circ }$
$\therefore$ Angle of dip, $\theta =60^{\circ }$