Question

If the vertical component of earth's magnetic field at a place is $\sqrt{3}$ times the horizontal component, then the value of dip at that place is

• A. $60^\circ $
• B. $45^\circ $
• C. $30^\circ $
• D. $15^\circ $

Answer 1

Answer: (A)

Here, $B_{V}=\sqrt{3} \, B_{H}$
We know that, angle of dip, $\theta=\tan ^{-1}\left(\frac{B_V}{B_H}\right)$
$\Rightarrow \theta=\tan ^{-1}\left(\frac{\sqrt{3} B_H}{B_H}\right)=\tan ^{-1}(\sqrt{3})=60^{\circ}$
$\therefore $ Angle of dip, $\theta =60^\circ $