Question

If the time period $t$ of the oscillation of a drop of liquid of density $d$, radius $r$, vibrating under surface tension $s$ is given by the formula $t=\sqrt{r^{2b}{s}^c{d}^{a/2}}.$ It is observed that the time period is directly proportional to $\sqrt{\frac{d}{s}}.$ The value of $b$ should therefore be :

• A. $\frac{3}{4}$
• B. $\sqrt{3}$
• C. $\frac{3}{2}$
• D. $\frac{2}{3}$

Answer 1

Answer: (C)

Correct answer is (c) $\frac{3}{2}$