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Q. If the time period $t$ of the oscillation of a drop of liquid of density $d$, radius $r$, vibrating under surface tension $s$ is given by the formula $t=\sqrt{r^{2b}s^{c}d^{a/2}}.$ It is observed that the time period is directly proportional to $\sqrt{\frac{d}{s}}.$ The value of $b$ should therefore be :

JEE MainJEE Main 2013Physical World, Units and Measurements

Solution:

Correct answer is (c) $\frac{3}{2}$