If the rate of reaction increases by 27 times, when temperature is increased by 30 K, then temperature coefficient of the reaction is

Question

If the rate of reaction increases by 27 times, when temperature is increased by 30 K, then temperature coefficient of the reaction is (A) 3 (B) 2 (C) 1 (D) 2.5

Tardigrade Admin · Accepted Answer

=2(T2-T1/10)=2(30-0/10) ⇒ 23 ⇒ 8 =3(T2-T1/10)=3(30-0/10) ⇒ 33 ⇒ 27 arrow i.e., temperature coefficient is 3 .

Q. If the rate of reaction increases by $27$ times, when temperature is increased by $30 K$ , then temperature coefficient of the reaction is

3

2

1

2.5

$= 2^{\frac{T _{2} - T _{1}}{10}} = 2^{\frac{30 - 0}{10}} \Rightarrow 2^{3} \Rightarrow 8$
$= 3^{\frac{T _{2} - T _{1}}{10}} = 3^{\frac{30 - 0}{10}} \Rightarrow 3^{3} \Rightarrow 27 \to$ i.e., temperature coefficient is $3$ .

Q. If the rate of reaction increases by 27 times, when temperature is increased by 30K, then temperature coefficient of the reaction is

3

2

1

2.5

=210T2​−T1​​=21030−0​⇒23⇒8 =310T2​−T1​​=31030−0​⇒33⇒27→ i.e., temperature coefficient is 3 .

Q. If the rate of reaction increases by $27$ times, when temperature is increased by $30 K$ , then temperature coefficient of the reaction is

$= 2^{\frac{T _{2} - T _{1}}{10}} = 2^{\frac{30 - 0}{10}} \Rightarrow 2^{3} \Rightarrow 8$
$= 3^{\frac{T _{2} - T _{1}}{10}} = 3^{\frac{30 - 0}{10}} \Rightarrow 3^{3} \Rightarrow 27 \to$ i.e., temperature coefficient is $3$ .