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Q. If the rate of reaction increases by $27$ times, when temperature is increased by $30 \,K$, then temperature coefficient of the reaction is

Chemical Kinetics

Solution:

$=2^{\frac{T_{2}-T_{1}}{10}}=2^{\frac{30-0}{10}} \Rightarrow 2^{3} \Rightarrow 8$
$=3^{\frac{T_{2}-T_{1}}{10}}=3^{\frac{30-0}{10}} \Rightarrow 3^{3} \Rightarrow 27 \rightarrow$ i.e., temperature coefficient is $3$ .