If the Planck’s constant h = 6.6 × 10-34 Js, the de Broglie wavelength of a particle having momentum of 3.3 × 10-24 kg ms-1 will be

Question

If the Planck’s constant h = 6.6 × 10-34 Js, the de Broglie wavelength of a particle having momentum of 3.3 × 10-24 kg ms-1 will be (A) 0.002 mathringA (B) 0.5 mathringA (C) 2 mathringA (D) 500 mathringA

Tardigrade Admin · Accepted Answer

λ = (h /p ) = (6.6 ×10-34/3.3 ×10-24) = 2 ×10-10 m = 2 mathringA

Q. If the Planck’s constant $h = 6.6 \times 1 0^{- 34} J s$ , the de Broglie wavelength of a particle having momentum of $3.3 \times 1 0^{- 24} k g m s^{- 1}$ will be

$0.002 \overset{˚}{A}$

$0.5 \overset{˚}{A}$

$2 \overset{˚}{A}$

$500 \overset{˚}{A}$

$λ = \frac{h}{p} = \frac{6.6 \times 1 0 ^{- 34}}{3.3 \times 1 0 ^{- 24}}$
$= 2 \times 1 0^{- 10} m = 2 \overset{˚}{A}$

Q. If the Planck’s constant h=6.6×10−34Js, the de Broglie wavelength of a particle having momentum of 3.3×10−24kgms−1 will be

0.002A˚

0.5A˚

2A˚

500A˚