1. Tardigrade
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  3. Chemistry
  4. If the Planck’s constant h = 6.6 × 10-34 Js, the de Broglie wavelength of a particle having momentum of 3.3 × 10-24 kg ms-1 will be

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Q. If the Planck’s constant $h = 6.6 \times 10^{-34} \, Js$, the de Broglie wavelength of a particle having momentum of $3.3 \times 10^{-24} \, kg \, ms^{-1}$ will be

BITSATBITSAT 2018

Solution:

$\lambda = \frac{h }{p } = \frac{6.6 \times10^{-34}}{3.3 \times10^{-24}}$
$ = 2 \times10^{-10} m = 2 \,\mathring{A} $