If the orbital radius of the electron in a hydrogen atom is 4.7 × 10-11 m. Compute the kinetic energy of the electron in hydrogen atom.

Question

If the orbital radius of the electron in a hydrogen atom is 4.7 × 10-11 m. Compute the kinetic energy of the electron in hydrogen atom. (A) 15.3 eV (B) -15.3 eV (C) 13.6 e (D) -13.6 eV

Tardigrade Admin · Accepted Answer

K=(e2/8 π ε0 r) =((9 × 109 Nm 2 / C 2)(1.6 × 10-19 C )2/(2)(4.7 × 10-11 m )) =2.45 × 10-18 J =15.3 eV

Q. If the orbital radius of the electron in a hydrogen atom is $4.7 \times 1 0^{- 11} m$ . Compute the kinetic energy of the electron in hydrogen atom.

15.3 eV

-15.3 eV

13.6 e

-13.6 eV

$K = \frac{e ^{2}}{8 π ε _{0} r} = \frac{( 9 \times 1 0 ^{9} N m ^{2} / C ^{2} ) ( 1.6 \times 1 0 ^{- 19} C ) ^{2}}{( 2 ) ( 4.7 \times 1 0 ^{- 11} m )}$
$= 2.45 \times 1 0^{- 18} J$
$= 15.3 e V$

Q. If the orbital radius of the electron in a hydrogen atom is 4.7×10−11m. Compute the kinetic energy of the electron in hydrogen atom.