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  4. If the orbital radius of the electron in a hydrogen atom is 4.7 × 10-11 m. Compute the kinetic energy of the electron in hydrogen atom.

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Q. If the orbital radius of the electron in a hydrogen atom is $4.7 \times 10^{-11} m$. Compute the kinetic energy of the electron in hydrogen atom.

Atoms

Solution:

$K=\frac{e^{2}}{8 \pi \varepsilon_{0} r} =\frac{\left(9 \times 10^{9} Nm ^{2} / C ^{2}\right)\left(1.6 \times 10^{-19} C \right)^{2}}{(2)\left(4.7 \times 10^{-11} m \right)} $
$=2.45 \times 10^{-18} J$
$=15.3\, eV$