If the momentum of a particle is doubled, then its de-Broglie wavelength will:

Question

If the momentum of a particle is doubled, then its de-Broglie wavelength will: (A) remain unchanged (B) become four times (C) become two times (D) become half

Tardigrade Admin · Accepted Answer

According to de-Broglie theory, the wavelength λ =( textPlank ! ! ! ! text s textconstant/ textmomentum) ⇒ λ propto (1/p) Hence, if momentum of particle is doubled then it is clear that wavelength will become half.

Q. If the momentum of a particle is doubled, then its de-Broglie wavelength will:

remain unchanged

become four times

become two times

become half

According to de-Broglie theory, the wavelength $λ = \frac{Plank s constant}{momentum}$ $\Rightarrow$ $λ \propto \frac{1}{p}$ Hence, if momentum of particle is doubled then it is clear that wavelength will become half.

Q. If the momentum of a particle is doubled, then its de-Broglie wavelength will:

remain unchanged

become four times

become two times

become half

According to de-Broglie theory, the wavelength λ=momentumPlank sconstant​ ⇒ λ∝p1​ Hence, if momentum of particle is doubled then it is clear that wavelength will become half.

According to de-Broglie theory, the wavelength $λ = \frac{Plank s constant}{momentum}$ $\Rightarrow$ $λ \propto \frac{1}{p}$ Hence, if momentum of particle is doubled then it is clear that wavelength will become half.