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Q.
If the momentum of a particle is doubled, then its de-Broglie wavelength will:
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Solution:
According to de-Broglie theory, the wavelength $ \lambda =\frac{\text{Plank }\!\!\!\!\text{ s}\,\text{constant}}{\text{momentum}} $ $ \Rightarrow $ $ \lambda \propto \frac{1}{p} $ Hence, if momentum of particle is doubled then it is clear that wavelength will become half.