If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be

Question

If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be (A) 1.57 (B)  3.17 (C)  6.28 (D) 12.56

Tardigrade Admin · Accepted Answer

V max =a max ω A=ω2 A ω=1 (2 π/ T )=1 T=2 π T=6.28 sec

Q. If the maximum velocity and acceleration of a particle executing $S H M$ are equal in magnitude, the time period will be

$1.57$

$3.17$

$6.28$

$12.56$

$V_{m a x} = a_{m a x}$
$ω A = ω^{2} A$
$ω = 1$
$\frac{2 π}{T} = 1$
$T = 2 π$
$T = 6.28 sec$

Q. If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be

1.57

3.17

6.28

12.56