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  4. If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be

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Q. If the maximum velocity and acceleration of a particle executing $SHM$ are equal in magnitude, the time period will be

Oscillations

Solution:

$V_{\max }=a_{\max }$
$\omega A=\omega^{2} A$
$\omega=1$
$\frac{2 \pi}{ T }=1$
$T=2 \pi$
$T=6.28\, sec$