If the intermolecular forces vanish away, the volume occupied by the molecules contained in 4.5 kg water of NTP will be given by

Question

If the intermolecular forces vanish away, the volume occupied by the molecules contained in 4.5 kg water of NTP will be given by (A)  5.6 m3  (B)  4.5 m3  (C)  11.2 m3  (D) 5.6L

Tardigrade Admin · Accepted Answer

Due to vanishing of intermolecular forces, the liquid would get converted into vapour.
We know that

18 \times 1 0^{- 3} k g

of water vapour occupies a volume of

22.4 \times 1 0^{- 3} m^{3}

at NTP.
So, volume occupied by

4.5 k g

is

\frac{22.4 \times 1 0 ^{- 3}}{18 \times 1 0 ^{- 3}} \times 4.5 m^{3}

= 5.6 m^{3}

Q. If the intermolecular forces vanish away, the volume occupied by the molecules contained in $4.5 k g$ water of NTP will be given by

$5.6 m^{3}$

$4.5 m^{3}$

$11.2 m^{3}$

5.6L

Q. If the intermolecular forces vanish away, the volume occupied by the molecules contained in 4.5kg water of NTP will be given by

5.6m3

4.5m3

11.2m3

5.6L

Due to vanishing of intermolecular forces, the liquid would get converted into vapour. We know that 18×10−3kg of water vapour occupies a volume of 22.4×10−3m3 at NTP. So, volume occupied by 4.5kg is 18×10−322.4×10−3​×4.5m3 =5.6m3

Q. If the intermolecular forces vanish away, the volume occupied by the molecules contained in $4.5 k g$ water of NTP will be given by

$5.6 m^{3}$

$4.5 m^{3}$

$11.2 m^{3}$