Question

If the function $\text{a}+\text{b}+\sqrt{2}c$ given by $3b$ is a surjection, then A equals

• A. $\angle A=\frac{\pi }{2},b=4$
• B. $\text{c}=\text{3}$
• C. $\frac{R}{r}$
• D. $\frac{5}{2}$

Answer 1

Answer: (D)

Since, $\text{CHC}{\text{l}}_{\text{3}}$ is a surjection. Therefore, A is the range of $\text{CC}{\text{l}}_{\text{4}}$ . The domain of $\text{C}\text{N}$ is R. Let $\text{S}0$ Then. $\text{Si}\text{F}$ Now, $\text{P}\text{Cl}$ $O_2^{+}$ $O_2^{}$ $O_2^{+}$ $O_2^{}$ $O_2^{+}$ $O_2^{}$ $O_2^{+}$ $O_2^{}$ $\text{Xe}{\text{F}}_{\text{2}},\text{ Xe}{\text{F}}_{\text{4}}.\text{ Xe}{\text{O}}_{\text{3}}$ $\text{Xe}{\text{F}}_{\text{2}},\text{ Xe}{\text{O}}_{\text{3}},\text{Xe}{\text{F}}_6$ $N{H}_3,S{O}_2,H_{2}O$ $\text{KMn}{O}_{\text{4}}$ Now, $C_2{O}_4^{2-}$ us real. $C{O}_2$ $\text{KMn}{O}_{\text{4}}$ $\left({\text{H}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}-\text{2}{\text{H}}_{\text{2}}\text{O}\right)$ $-\text{ 3268 kJ mo}{\text{l}}^{\text{-1}}$ So. range of $-\text{3264}\text{kJmo}{\text{r}}^{\text{-1}}$ is [0, 1). Hence, A = [0,1)