Question

If the frequency of light in a photoelectric experiment is doubled, the stopping potenital will

• A. be doubled
• B. be halved
• C. become more than double
• D. become less than double

Answer 1

Answer: (C)

The energy equation is given as,
$e{V}_0=hv-W$
$V_0=\frac{hv}{e}-\frac{W}{e}$
When the frequency is doubled,
$V_0{}^{\prime }=\frac{2hv}{e}-\frac{W}{e}$
$V_0{}^{\prime }=2\left(\frac{hv}{e}-\frac{W}{e}\right)+\frac{W}{e}$
$V_0{}^{\prime }=2V_0+\frac{W}{e}$
$V_0{}^{\prime }>2V_0$
Thus, the stopping potential will become more than doubled.