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  4. If the frequency of light in a photoelectric experiment is doubled, the stopping potenital will

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Q. If the frequency of light in a photoelectric experiment is doubled, the stopping potenital will

Dual Nature of Radiation and Matter

Solution:

The energy equation is given as,
$eV _{0}= hv - W$
$V _{0}=\frac{ hv }{ e }-\frac{ W }{ e }$
When the frequency is doubled,
$V _{0}{ }'=\frac{2 hv }{ e }-\frac{ W }{ e }$
$V _{0}{ }'=2\left(\frac{ hv }{ e }-\frac{ W }{ e }\right)+\frac{ W }{ e }$
$V _{0}{ }'=2 V _{0}+\frac{ W }{ e }$
$V _{0}{ }'>2 V _{0}$
Thus, the stopping potential will become more than doubled.