If the equation for the displacement of a particle moving on a circular path is given by (θ)= 2 t3+0.5 where θ is in radians and t in seconds, then the angular velocity of the particleat t = 2 sec, is

Question

If the equation for the displacement of a particle moving on a circular path is given by (θ)= 2 t3+0.5 where θ is in radians and t in seconds, then the angular velocity of the particleat t = 2 sec, is (A) 24 rad/sec (B) 12 rad/sec (C) 8 rad/sec (D) 36 rad/sec

Tardigrade Admin · Accepted Answer

Angular velocity, ω=(d θ/d t)=6 t2 at t=2 sec w=6 × 4=24 rad / sec .

Q. If the equation for the displacement of a particle moving on a circular path is given by $(θ) =$ $2 t^{3} + 0.5$ where $θ$ is in radians and $t$ in seconds, then the angular velocity of the particleat $t = 2 sec$ , is

24 rad/sec

12 rad/sec

8 rad/sec

36 rad/sec

Angular velocity, $ω = \frac{d θ}{d t} = 6 t^{2}$
at $t = 2 sec$
$w = 6 \times 4 = 24 r a d / sec .$

Q. If the equation for the displacement of a particle moving on a circular path is given by (θ)= 2t3+0.5 where θ is in radians and t in seconds, then the angular velocity of the particleat t=2sec, is