Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If the equation for the displacement of a particle moving on a circular path is given by $(\theta)=$ $2 t^{3}+0.5$ where $\theta$ is in radians and $t$ in seconds, then the angular velocity of the particleat $t = 2\, sec$, is

AIIMSAIIMS 1998System of Particles and Rotational Motion

Solution:

Angular velocity, $\omega=\frac{d \theta}{d t}=6 t^{2}$
at $t=2\, sec$
$w=6 \times 4=24\, rad / sec .$