If the energy released in the fission of one nucleus is 3.2 × 10-11 J, then number of nuclei required per second in a power plant of 16 kW is

Question

If the energy released in the fission of one nucleus is 3.2 × 10-11 J, then number of nuclei required per second in a power plant of 16 kW is (A) 0.5 × 1014 (B)  0.5× 1012  (C)  5× 1012  (D)  5× 1014

Tardigrade Admin · Accepted Answer

The number of nuclei required per second is n=(P/E)=(16 × 103/3.2 × 10-11) =5 × 1014

Q. If the energy released in the fission of one nucleus is $3.2 \times 1 0^{- 11} J$ , then number of nuclei required per second in a power plant of $16 kW$ is

$0.5 \times 1 0^{14}$

$0.5 \times 1 0^{12}$

$5 \times 1 0^{12}$

$5 \times 1 0^{14}$

The number of nuclei required per second is
$n = \frac{P}{E} = \frac{16 \times 1 0 ^{3}}{3.2 \times 1 0 ^{- 11}}$
$= 5 \times 1 0^{14}$

Q. If the energy released in the fission of one nucleus is 3.2×10−11J, then number of nuclei required per second in a power plant of 16kW is

0.5×1014

0.5×1012

5×1012

5×1014