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  4. If the energy released in the fission of one nucleus is 3.2 × 10-11 J, then number of nuclei required per second in a power plant of 16 kW is

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Q. If the energy released in the fission of one nucleus is $3.2 \times 10^{-11} \,J$, then number of nuclei required per second in a power plant of $16 \,kW$ is

JIPMERJIPMER 2003Nuclei

Solution:

The number of nuclei required per second is
$n=\frac{P}{E}=\frac{16 \times 10^{3}}{3.2 \times 10^{-11}}$
$=5 \times 10^{14}$