If the electric current through an electric bulb is 3.2 A, the number of electrons flow through it in one second is

Question

If the electric current through an electric bulb is 3.2 A, the number of electrons flow through it in one second is (A)  2× 109 (B)  2× 1019 (C)  3.2× 1019 (D)  1.6× 1018

Tardigrade Admin · Accepted Answer

I=(n e/t) 3.2=(n × 1.6 × 10-19/1) n=(3.2/1.6 × 10-19) =2 × 1019

Q. If the electric current through an electric bulb is $3.2 A,$ the number of electrons flow through it in one second is

$2 \times 1 0^{9}$

$2 \times 1 0^{19}$

$3.2 \times 1 0^{19}$

$1.6 \times 1 0^{18}$

$I = \frac{n e}{t} 3.2 = \frac{n \times 1.6 \times 1 0 ^{- 19}}{1}$
$n = \frac{3.2}{1.6 \times 1 0 ^{- 19}}$
$= 2 \times 1 0^{19}$

Q. If the electric current through an electric bulb is 3.2A, the number of electrons flow through it in one second is

2×109

2×1019

3.2×1019

1.6×1018