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Q. If the electric current through an electric bulb is $ 3.2\,A, $ the number of electrons flow through it in one second is

J & K CETJ & K CET 2007Current Electricity

Solution:

$I=\frac{n e}{t} 3.2=\frac{n \times 1.6 \times 10^{-19}}{1}$
$n=\frac{3.2}{1.6 \times 10^{-19}}$
$=2 \times 10^{19}$