If the earth were to rotates faster than its present speed, the weight of an object will

Question

If the earth were to rotates faster than its present speed, the weight of an object will (A) increase at the equator but remain unchanged at the poles (B) decrease at the equator but remain unchanged at the poles (C) remain unchanged at the equator but decrease at the poles (D) remain unchanged at the equator but increase at the poles

Tardigrade Admin · Accepted Answer

At the equator, g prime=g-R ω2 As ω increases, g prime decreases and hence weight decreases. At the pole, g prime=g. So weight remain unchanged.

Q. If the earth were to rotates faster than its present speed, the weight of an object will

increase at the equator but remain unchanged at the poles

decrease at the equator but remain unchanged at the poles

remain unchanged at the equator but decrease at the poles

remain unchanged at the equator but increase at the poles

At the equator, $g^{'} = g - R ω^{2}$
As $ω$ increases, $g^{'}$ decreases and hence weight decreases.
At the pole, $g^{'} = g$ .
So weight remain unchanged.

Q. If the earth were to rotates faster than its present speed, the weight of an object will

increase at the equator but remain unchanged at the poles

decrease at the equator but remain unchanged at the poles

remain unchanged at the equator but decrease at the poles

remain unchanged at the equator but increase at the poles

At the equator, g′=g−Rω2 As ω increases, g′ decreases and hence weight decreases. At the pole, g′=g. So weight remain unchanged.

At the equator, $g^{'} = g - R ω^{2}$
As $ω$ increases, $g^{'}$ decreases and hence weight decreases.
At the pole, $g^{'} = g$ .
So weight remain unchanged.