If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light (in nm) used is

Question

If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light (in nm) used is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

There are three and a half fringes from first maxima to fifth minima as shown. ⇒ β=(7 mm /3.5)=2 mm ⇒ λ=(β d/D)=600 nm <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/f4d8a4d409a7f7758970b23d2f1e23b5-.png" />

Q. If the distance between the first maxima and fifth minima of a double slit pattern is $7 mm$ and the slits are separated by $0.15 mm$ with the screen $50 c m$ from the slits, then wavelength of the light (in nm) used is

There are three and a half fringes from first maxima to fifth minima as shown.
$\Rightarrow β = \frac{7 mm}{3.5} = 2 mm$
$\Rightarrow λ = \frac{β d}{D} = 600 nm$

Q. If the distance between the first maxima and fifth minima of a double slit pattern is 7mm and the slits are separated by 0.15mm with the screen 50cm from the slits, then wavelength of the light (in nm) used is

There are three and a half fringes from first maxima to fifth minima as shown. ⇒β=3.57mm​=2mm ⇒λ=Dβd​=600nm

Q. If the distance between the first maxima and fifth minima of a double slit pattern is $7 mm$ and the slits are separated by $0.15 mm$ with the screen $50 c m$ from the slits, then wavelength of the light (in nm) used is

There are three and a half fringes from first maxima to fifth minima as shown.
$\Rightarrow β = \frac{7 mm}{3.5} = 2 mm$
$\Rightarrow λ = \frac{β d}{D} = 600 nm$