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Q. If the distance between the first maxima and fifth minima of a double slit pattern is $7\, mm$ and the slits are separated by $0.15\, mm$ with the screen $50\, cm$ from the slits, then wavelength of the light (in nm) used is

Wave Optics

Solution:

There are three and a half fringes from first maxima to fifth minima as shown.
$\Rightarrow \beta=\frac{7 mm }{3.5}=2 mm$
$\Rightarrow \lambda=\frac{\beta d}{D}=600\, nm$
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