If the displacement of a particle executing SHM is given by, y=0.30sin(220 t + 0 . 64) in meters , then the frequency and the maximum velocity of the particle is,

Question

If the displacement of a particle executing SHM is given by, y=0.30sin(220 t + 0 . 64) in meters , then the frequency and the maximum velocity of the particle is, (A) 35Hz text,66ms- 1 (B) 45Hz text,66ms- 1 (C) 58Hz text,113ms- 1 (D) 35Hz text,132ms- 1

Tardigrade Admin · Accepted Answer

n=(ω /2 π )=(220/2 π )=35Hz vmax=ω a=220× 0.30ms- 1=66ms- 1

Q. If the displacement of a particle executing SHM is given by, $y = 0.30 s in (220 t + 0.64)$ in $m e t ers$ , then the frequency and the maximum velocity of the particle is,

$35 Hz, 66 m s^{- 1}$

$45 Hz, 66 m s^{- 1}$

$58 Hz, 113 m s^{- 1}$

$35 Hz, 132 m s^{- 1}$

$n = \frac{ω}{2 π} = \frac{220}{2 π} = 35 Hz$
$v_{ma x} = ωa = 220 \times 0.30 m s^{- 1} = 66 m s^{- 1}$

Q. If the displacement of a particle executing SHM is given by, y=0.30sin(220t+0.64) in meters , then the frequency and the maximum velocity of the particle is,

35Hz,66ms−1

45Hz,66ms−1

58Hz,113ms−1

35Hz,132ms−1