Question

If the displacement of a particle executing SHM is given by, $y=0.30sin\left(220 t + 0 . 64\right)$ in $meters$ , then the frequency and the maximum velocity of the particle is,

• A. $35Hz\text{,}66ms^{- 1}$
• B. $45Hz\text{,}66ms^{- 1}$
• C. $58Hz\text{,}113ms^{- 1}$
• D. $35Hz\text{,}132ms^{- 1}$

Answer 1

Answer: (A)

$n=\frac{\omega }{2 \pi }=\frac{220}{2 \pi }=35Hz$
$v_{max}=\omega a=220\times 0.30ms^{- 1}=66ms^{- 1}$