Question

If the density of water is $1gc{m}^{-3}$ then, the volume occupied by one molecule of water is approximately

• A. $18c{m}^3$
• B. $22400c{m}^3$
• C. $6.02\times {10}^{-23}c{m}^3$
• D. $3.0\times {10}^{-23}c{m}^3$

Answer 1

Answer: (D)

Mass of one molecule of water $=\frac{\text{mol}\text{.}\text{mass}}{{\text{N}}_{\text{0}}}=\frac{18}{6.02\times {10}^{23}}g$ $\therefore$ Volume of 1 molecule of water $=\frac{\text{mass}}{\text{density}}$ $=\frac{18\times {10}^{-23}}{6.02\times 1}$ $=3\times {10}^{-23}mL$