Question

If the density of water is $ 1\,gc{{m}^{-3}} $ then, the volume occupied by one molecule of water is approximately

• A. $ 18\,c{{m}^{3}} $
• B. $ 22400\,c{{m}^{3}} $
• C. $ 6.02\times {{10}^{-23}}c{{m}^{3}} $
• D. $ 3.0\times {{10}^{-23}}\,c{{m}^{3}} $

Answer 1

Answer: (D)

Mass of one molecule of water $ =\frac{\text{mol}\text{.}\,\text{mass}}{{{\text{N}}_{\text{0}}}}=\frac{18}{6.02\times {{10}^{23}}}g $ $ \therefore $ Volume of 1 molecule of water $ =\frac{\text{mass}}{\text{density}} $ $ =\frac{18\times {{10}^{-23}}}{6.02\times 1} $ $ =3\times {{10}^{-23}}mL $