Question

If the density of water is 1 g $c{m}^{-3}$ then the volume occupied by one molecule of water is approximately

• A. $18c{m}^3$
• B. $22400$ $c{m}^3$
• C. $6.02\times 10^{-23}c{m}^3$
• D. $3.0\times 10^{-23}c{m}^3$

Answer 1

Answer: (D)

Mass of $1$ molecule of water
$=\frac{GMM}{N_0}=\frac{18}{6.02\times 10^{23}}g$
$\therefore$ Volume of $1$ molecule of water $=\frac{\text{Mass}}{\text{Density}}$
$=\frac{18\times 10^{-23}}{6.02\times 1}=3.0\times 10^{-23}$ mL